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3a^2-33a+54=0
a = 3; b = -33; c = +54;
Δ = b2-4ac
Δ = -332-4·3·54
Δ = 441
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{441}=21$$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-33)-21}{2*3}=\frac{12}{6} =2 $$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-33)+21}{2*3}=\frac{54}{6} =9 $
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